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[SQL 고득점 Kit] GROUP BY 본문
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📍 [고양이와 개는 몇 마리 있을까]
SELECT ANIMAL_TYPE, COUNT(*) AS count
FROM ANIMAL_INS
GROUP BY ANIMAL_TYPE
order by animal_type
📍 [동명 동물 수 찾기]
SELECT NAME, COUNT(*)
FROM ANIMAL_INS
WHERE NAME IS NOT NULL
GROUP BY NAME
HAVING COUNT(*)>1
ORDER BY NAME;
📍 [입양 시각 구하기(1)]
SELECT HOUR(DATETIME) AS HOUR, COUNT(DATETIME) AS COUNT
FROM animal_OUTS
WHERE HOUR(DATETIME) >= 9 AND HOUR(DATETIME) <=19
GROUP BY HOUR(DATETIME)
ORDER BY HOUR ;
📍 [입양 시각 구하기(2)]
SET @hour := 0;
SELECT (@hour) as HOUR,
(SELECT COUNT(*) FROM ANIMAL_OUTS WHERE HOUR(DATETIME) = @hour) as COUNT
FROM ANIMAL_OUTS
WHERE @hour < 23;
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